3x^2-4=79

Solution for 3x^2-4=79 equation:

3x^2-4=79

We move all terms to the left:

3x^2-4-(79)=0

We add all the numbers together, and all the variables

3x^2-83=0

a = 3; b = 0; c = -83;
Δ = b2-4ac
Δ = 02-4·3·(-83)
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{249}}{2*3}=\frac{0-2\sqrt{249}}{6}
=-\frac{2\sqrt{249}}{6}
=-\frac{\sqrt{249}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{249}}{2*3}=\frac{0+2\sqrt{249}}{6}
=\frac{2\sqrt{249}}{6}
=\frac{\sqrt{249}}{3}
$